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Re: Question for the maths experts
Posted: Sat Nov 29, 2008 6:41 pm
by ahunda
Ups. Didn´t realise, that this had sparked such an intense debate.
Just to clarify: I was indeed thinking of two separate fronts to take out one player.
For example a player, that has a few territories in North America and a few in Australia (taking the old Classic map as example here). And I can deploy my new armies in a way, that will give me a 50 % chance on each side (chose 50 to make it easy).
And in hindsight the question seems rather dumb and the correct answer (25 %) rather obvious to me.
Cheers.
Re: Question for the maths experts
Posted: Sat Nov 29, 2008 6:45 pm
by theconquerer1995
RashidJelzin wrote:Yeah that's easy...
you multiply both strings of possibilities, since it's 2 different fronts and they're not dependent on each other.
So it's (50/100) x (50/100) = (2500/10000) = (25/100) = 25%
Well that's how I remember it... and I'm pretty sure I got that right.
If I dare advise you... don't take 50% shots. That's suicide.
There's the math genius right there
Re: Question for the maths experts
Posted: Sat Nov 29, 2008 9:12 pm
by knubbel
Geger wrote:BaldAdonis wrote:knubbel wrote:How do you guys calculate the propability of killing an enemy? Do you have a programm? I always just try to guess, but sometimes I would like to calculate it exact.
http://gamesbyemail.com/Games/Gambit/BattleOdds
Thanks for the link

That is not what I mean. I would like a calculator that tells me the propability of beating more than one country.
For example 10vs5 and the remaining armees vs 3. I know how to calculate it but its a lot of work to do it (especially if there are more than 2 countrys). Does such a program exist or do I have to write it?
Re: Question for the maths experts
Posted: Sat Nov 29, 2008 9:15 pm
by Timminz
knubbel wrote:Geger wrote:BaldAdonis wrote:knubbel wrote:How do you guys calculate the propability of killing an enemy? Do you have a programm? I always just try to guess, but sometimes I would like to calculate it exact.
http://gamesbyemail.com/Games/Gambit/BattleOdds
Thanks for the link

That is not what I mean. I would like a calculator that tells me the propability of beating more than one country.
For example 10vs5 and the remaining armees vs 3. I know how to calculate it but its a lot of work to do it (especially if there are more than 2 countrys). Does such a program exist or do I have to write it?
That link will give you that information. just separate the numbers with a coma. I that case, type "10" in the first box, and "5,3" in the second
Re: Question for the maths experts
Posted: Sat Nov 29, 2008 9:29 pm
by knubbel
That link will give you that information. just separate the numbers with a coma. I that case, type "10" in the first box, and "5,3" in the second[/quote]
Thanks, very useful!
Re: Question for the maths experts
Posted: Mon Dec 01, 2008 5:55 pm
by RashidJelzin
Ahem. 25%. Who was right? Ah yeah, me.
Re: Question for the maths experts
Posted: Tue Dec 02, 2008 2:07 am
by hammocksleeper
ahunda wrote:Ups. Didn´t realise, that this had sparked such an intense debate.
Just to clarify: I was indeed thinking of two separate fronts to take out one player.
For example a player, that has a few territories in North America and a few in Australia (taking the old Classic map as example here). And I can deploy my new armies in a way, that will give me a 50 % chance on each side (chose 50 to make it easy).
And in hindsight the question seems rather dumb and the correct answer (25 %) rather obvious to me.
Cheers.
yes, 25%

Re: Question for the maths experts
Posted: Fri Jan 02, 2009 6:59 am
by Geger
I have other another question for the math experts :
I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.
What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory
Thanks

Re: Question for the maths experts
Posted: Sat Jan 03, 2009 10:39 am
by lancehoch
Geger wrote:I have other another question for the math experts :
I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.
What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory
Thanks

All 3: .45^3 = 0.091125 = 9.1125%
2+ of 3: .45^3+3*(.45^2*.55) = .42525 = 42.525%
1+ of 3: .45^3+3*(.45^2*.55)+3*(.45*.55^2) = 0.833625 = 83.3625%
Re: Question for the maths experts
Posted: Sat Jan 03, 2009 11:06 am
by Aradhus
I have a question, its not a maths question per se, but it is about maths, and maybe some math experts might know of an answer.
Does anybody know of a math site that teaches you from the basics of high school and upwards? I really want to get back my math skills, and the only way to do that for me would be at the beginning. I found a semi decent site before, but the day after, my laptop died, and when I got a new one I couldn't find the site again.
Can anybody help?
Re: Question for the maths experts
Posted: Sat Jan 03, 2009 11:38 am
by Geger
lancehoch wrote:Geger wrote:I have other another question for the math experts :
I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.
What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory
Thanks

All 3: .45^3 = 0.091125 = 9.1125%
2+ of 3: .45^3+3*(.45^2*.55) = .42525 = 42.525%
1+ of 3: .45^3+3*(.45^2*.55)+3*(.45*.55^2) = 0.833625 = 83.3625%
Thanks lancehoch

Using
http://gamesbyemail.com/Games/Gambit/BattleOdds, if I put 3 troops in 1 territorry and attack 3 nearby territories in follow (all have 3 troops inside), the odds are :
1+ of 3 : 76.9%
2+ of 3 : 29.4%
all 3 : 5.2%
Now... If I put in 3 territories of mine 1 troop each, the odd to conquer their nearby territories with 3 troops inside is 47.02511%. Now I use your formula :
1+ of 3 : .... = 85.1%
2+ of 3 : .... = 45.5%
all 3 : .... = 10.4%
Interesting

Do anybody want to play 1vs1 doodle?
