Max. number of cards a player can finish with? ANSWER

[Robinette]

i wonder what the most # of cards someone HAS finished with in a REAL game...



oh heck, i'd even be interested to see a phony build game that went for the max # of cards... has that been done?

[maxatstuy]

i wonder what the most # of cards someone HAS finished with in a REAL game...



oh heck, i'd even be interested to see a phony build game that went for the max # of cards... has that been done?

I asked *manimal earlier today and he doesnt want to make the multies and give it a try

lol

[whitestazn88]

dude... you can take 5 cards from other people though.... what if you were in an 8 player game, had 4 cards, then eliminated everyone else before they started?

that would be 39 cards....

[maxatstuy]

dude... you can take 5 cards from other people though.... what if you were in an 8 player game, had 4 cards, then eliminated everyone else before they started?

that would be 39 cards....

you can only kill one person before you would have to cash with 9 cards

[whitestazn88]

dude... you can take 5 cards from other people though.... what if you were in an 8 player game, had 4 cards, then eliminated everyone else before they started?

that would be 39 cards....

you can only kill one person before you would have to cash with 9 cards

good point. so then what's the most cards? i can't figure it out...

[PepperJack]

good point. so then what's the most cards? i can't figure it out...

[/quote]

While you may not be the whitestazn you are definitely not the positivestereotypeazn.

[whitestazn88]

using everyone's deadbeat logic, isn't 40 the correct answer?

all 8 get 5 cards, then all of them deadbeat while one just starts turns and leaves the game for an hour, no new card, no penalty....

[yeti_c]

using everyone's deadbeat logic, isn't 40 the correct answer?

all 8 get 5 cards, then all of them deadbeat while one just starts turns and leaves the game for an hour, no new card, no penalty....

Ya.

C.

[THE ARMY]

A Deadbeats his 5 to B =10
B Deadbeats his 10 to C =15

E Deadbeats his 5 to F =10
F Deadbeats his 10 to G =15

D takes G= 19
D Deadbeats to C= 34

H takes C= 38

So to start
A=5
B=5
C=5
D=4
E=5
F=5
G=5
H=4

To be honest i even thought it was 32 till someone came up with this one!!!

[Natewolfman]

wow... i didnt know cards got transfered every deadbeat has been without cards that ive played with lol

[Natewolfman]

oh heck, i'd even be interested to see a phony build game that went for the max # of cards... has that been done?

in!

[THE ARMY]

Yeah i didn't know that either and that is why i thought the answer was 32 but i guess they do since others say so, haha.

wow... i didnt know cards got transfered every deadbeat has been without cards that ive played with lol

[PLAYER57832]

Its actually 36 I believe. 8 player doubles game

Team 1 player A has 5 cards, deadbeats, give player B 10 cards.
Player C of team 2 has 4 cards and kills player B, giving player C 14 cards.
Player C deadbeats giving teammate player D who had 5 cards, 19 cards.
Player E of team 3 has 4 cards and kills player D, giving him/her 23 cards.
Player G of team 4 kills player E, giving him/her 27 cards.
Player G deadbeats, giving teammate player H, who already had 5 cards, 32 cards.
Player F of team 3 had 4 cards and kills player H and the game is over and he has 36 cards.

Except cards don't transfer unless you take out the deadbeat.

The basic answer is 9. You can begin a turn with 5, take someone over to win and get 9.

HOWEVER, I think if you win by objective, then you do get the other player's cards (?????) In that case, you could potentially have 39, if every player except you ended their turn with 5 cards (remember, they don't cash until their turn starts). The most you could begin with would be 4 (5 & you have to cash, going back down to 2). 7*5 + 4 = 39

[Fipa]

I believe the correct answer is 39.
Let's look at team 1 first.Player A deadbeats, and gives his cards to player B, who deadbeats and gives 10 cards to player C, who also deadbeats and give player D 15 cards. Player D now has 20 cards. Meanwhile, Player E (from team 2), deadbeats and gives player F 5 cards. Player F gives player G 10 cards. Now player D has 20 cards, player G has 15 cards and player H has 4 cards. Player H now takes his buddy out. So he has 19 cards. So you all say he has to cash in, and I agree, but he doesn't, instead, he runs out of time, and gets left with 19 cards. Played D deadbeats and player H wins the game with 39 cards! Correct me if I'm wrong.

[lancehoch]

Correct me if I'm wrong.

Ok. If player D deadbeats, then his cards do not go to player G. You are almost there. Eight player freestyle quads game: Team 1: A deadbeats gives his 5 to B (10), who deadbeats, C has 15. Team 2: E and F deadbeat, G has 15 cards. Next turn, D has 4 cards, takes out G (19) and C deadbeats, D (34). Next turn, H has 4 cards and takes out D (38).

[maxatstuy]

If you are including team games, (which I was not considering earlier because if any of my teammate were to deadbeat, cards are the last thing on my mind,) then the number would change, but the most would be 38 cards, not 36 or 33 which I said earlier.

In 8 player quads

Player A has 5 cards- deadbeats
B gets the cards so B now has 10 cards- deadbeats
C now has 15 cards
E kills C so now he has 19 cards- deabeats
F now has 24 cards- deadbeats
G now has 29 cards- deadbeats
H now has 34 cards
Player D who had 4 cards kills him and now has 38 cards

the most is 38 in a team game; for non team games, the equation is still (4n+1)

I wasnt aware of the deadbeating cards transfer either (until this thread) but I believe that my statement above is therefore the correct solution. No matter how it is calculated, it wouldnt be 32, it would be 33 or more since the first person eliminated could have 5 cards, not 4.

[Fipa]

Correct me if I'm wrong.

Ok. If player D deadbeats, then his cards do not go to player G. You are almost there. Eight player freestyle quads game: Team 1: A deadbeats gives his 5 to B (10), who deadbeats, C has 15. Team 2: E and F deadbeat, G has 15 cards. Next turn, D has 4 cards, takes out G (19) and C deadbeats, D (34). Next turn, H has 4 cards and takes out D (38).

Sorry didn't know that. How about this then: 8 player sequential game on the oasis map. Everybody has 5 cards except for player G who has 4 cards, and it's his turn. He takes the 3 grand oasis, finishes his turn and gets a card. Which now leaves everybody with 5 cards. Everybody misses a turn, player G starts it, but he does not have to cash in, because he automatically wins for holding the grand oasis. No deadbeats here. I could do a similar thing with the arms race map. If I'm wrong here too, I give up

[whitestazn88]

so then everyone is allowed to get 5 cards except 1 guy, he wins an objective (lets say they let him hold the sanctuary) and then he gets all the cards right?

so the max would be 39, like my first answer. right?

wtf is the answer?

[Fipa]

No, that's not what I said. He/she is holding the objective, with everybody having 5 cards. All the players miss a turn, and he wins automatically the game, leaving him with 40 cards

[Fipa]

Sorry didn't know that. How about this then: 8 player sequential game on the oasis map. Everybody has 5 cards except for player G who has 4 cards, and it's his turn. He takes the 3 grand oasis, finishes his turn and gets a card. Which now leaves everybody with 5 cards. Everybody misses a turn, player G starts it, but he does not have to cash in, because he automatically wins for holding the grand oasis. No deadbeats here. I could do a similar thing with the arms race map. If I'm wrong here too, I give up

I just realized that you don't get the opponents cards if you win by completing a quest, so I guess the answer is 38.

[THE ARMY]

Ok we know for sure the answer is 32 because that is easy to figure out. What we don't know is if cards transfer when people die. If they do then only in Team games would they transfer to team members, they would not transfer on sequential maps as this has happened to almost everyone before. So in theory the total would be 38 but nobody has ever tried it before. Therefore we must conclude that it is a CC mystery that will never be solved unless the day of reckoning comes and the actual game is played out. But be careful the day that comes might me the judgement day for us all.

[Fipa]

Hey I'm up for that game

[Robinette]

i wonder what the most # of cards someone HAS finished with in a REAL game...

[whitestazn88]

i wonder what the most # of cards someone HAS finished with in a REAL game...

calm down robinette... i think they're working on it

[maxatstuy]

Ok we know for sure the answer is 32 because that is easy to figure out. What we don't know is if cards transfer when people die. If they do then only in Team games would they transfer to team members, they would not transfer on sequential maps as this has happened to almost everyone before. So in theory the total would be 38 but nobody has ever tried it before. Therefore we must conclude that it is a CC mystery that will never be solved unless the day of reckoning comes and the actual game is played out. But be careful the day that comes might me the judgement day for us all.

33! not 32

try adding 5 + 4 + 4 + 4 + 4 + 4 + 4 + 4 and see what you get...Ill give you a hint, its an odd number one more than 32

and in the quads game, it would be 38 cards maximum as I previously stated