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Sir. Ricco wrote:Hmm… very interesting.I don’t know though. I think it would give the attack a little too much advantage.
Herakilla wrote:Sir. Ricco wrote:Hmm… very interesting.I don’t know though. I think it would give the attack a little too much advantage.
and defense too much advantage in beginning making it hard to start out
Herakilla wrote:the extra dice that attackers get really only gives the advantage in the long term, if you lose even one of those 5 your attacking with your already down an out a die. thats why when the numbers get higher on both sides the attacker gains more and more of an advantage
Herakilla wrote:one other thing, defenders would gain more of an advantage than attackers, each die you add adds another 1/6 chance to get a 6 which is an auto win for defenders with 3 you have a 3/6 of getting one 6 so effectively every other roll should have a 6 instead of every 6th 3rd roll and that can be painful
basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote:Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how to
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD
Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote:Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD
Risktaker17 wrote:Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote:Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD
Herakilla isn't the sharpest tool in the shed.![]()
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