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The Homework Help Thread

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The Homework Help Thread

Postby The Weird One on Mon Oct 01, 2007 5:08 pm

I couldn't find the old one, so, I decided to restart it (it was useful for a while)
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Postby GreecePwns on Mon Oct 01, 2007 5:50 pm

This should be stickied
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Postby hecter on Mon Oct 01, 2007 5:52 pm

I'm given the roots x=(2-i) and x=(2+i), and I need to turn it into the quadratic equation ax^2+bx+c=0 form. i stands for imaginary number.
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Postby unriggable on Mon Oct 01, 2007 5:53 pm

i = square root of -1. Plug it in, plug it in.
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Postby The Weird One on Mon Oct 01, 2007 5:53 pm

GreecePwns wrote:This should be stickied


ya
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Postby hecter on Mon Oct 01, 2007 5:56 pm

unriggable wrote:i = square root of -1. Plug it in, plug it in.

I know that. I even said that. It still doesn't help me though... I've tried some substitution with that, but it didn't work :(
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Postby 0ojakeo0 on Mon Oct 01, 2007 6:02 pm

how do u square a number on the comp?
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Postby unriggable on Mon Oct 01, 2007 6:02 pm

0ojakeo0 wrote:how do u square a number on the comp?


number times number.
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Postby GreecePwns on Mon Oct 01, 2007 6:02 pm

0ojakeo0 wrote:how do u square a number on the comp?


Type 5^2=25

Is that what you are asking?
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Postby Neutrino on Mon Oct 01, 2007 6:04 pm

hecter wrote:I'm given the roots x=(2-i) and x=(2+i), and I need to turn it into the quadratic equation ax^2+bx+c=0 form. i stands for imaginary number.


Define "roots"

I think I've done this question before, but the phrasing was better.
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Postby 0ojakeo0 on Mon Oct 01, 2007 6:04 pm

8^2 + 2t- 5t -8=?
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Postby Neutrino on Mon Oct 01, 2007 6:07 pm

Don't bother. I remember now. Just gimme a sec to work out how the Quadratic Formula works backwards...
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Postby hecter on Mon Oct 01, 2007 6:08 pm

hecter wrote:
unriggable wrote:i = square root of -1. Plug it in, plug it in.

I know that. I even said that. It still doesn't help me though... I've tried some substitution with that, but it didn't work :(

Yes! I figured it out!

x^2+5x+6=0 can be factored to:
(x+3)(x+2)=0 which means:
x=-3 and x=-2

That means that if I work my way backwards...
x=(2+i) and x=(2-i) so I get:
(x-2-i)(x-2+i) which is multiplied out to:
x^2-2x+xi-2x+4-2i-xi+2i-i^2
simplify that to:
x^2-4x+5 which means
a=1 b=-4 and c=5

:D
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Postby GreecePwns on Mon Oct 01, 2007 6:09 pm

0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Do you mean 8t^2?
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Postby 0ojakeo0 on Mon Oct 01, 2007 6:11 pm

GreecePwns wrote:
0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Do you mean 8t^2?


ya my bad its 8t^2 +3t-8 right?
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Postby Titanic on Mon Oct 01, 2007 6:30 pm

0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Um...wtf? You've got a variable, but only 1 side of the equations. Thats impossible because it just goes to 58-3t=?
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Postby 0ojakeo0 on Mon Oct 01, 2007 6:31 pm

Titanic wrote:
0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Um...wtf? You've got a variable, but only 1 side of the equations. Thats impossible because it just goes to 58-3t=?


someone pointed that out and i fixed it in the next post
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Postby GreecePwns on Mon Oct 01, 2007 6:33 pm

0ojakeo0 wrote:
GreecePwns wrote:
0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Do you mean 8t^2?


ya my bad its 8t^2 +3t-8 right?


No (2t - 5t = -3t), but it could be continued if you're asked to.
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Postby Titanic on Mon Oct 01, 2007 6:36 pm

0ojakeo0 wrote:
Titanic wrote:
0ojakeo0 wrote:8^2 + 2t- 5t -8=?


Um...wtf? You've got a variable, but only 1 side of the equations. Thats impossible because it just goes to 58-3t=?


someone pointed that out and i fixed it in the next post


Yer, soz, took too long to post. Btw, your new one, what is originally equal to? 0?
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Postby misterman10 on Mon Oct 01, 2007 6:46 pm

it was also titled the homework thread :wink:
whatev though, I guess my thread wasn't good enough :cry:

can anybody help me with my term paper and write it for me? thanks in advance :lol:
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Postby GreecePwns on Mon Oct 01, 2007 7:08 pm

misterman10 wrote:it was also titled the homework thread :wink:
whatev though, I guess my thread wasn't good enough :cry:

can anybody help me with my term paper and write it for me? thanks in advance :lol:
depends on the topic and if I have interest in it. :wink:
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Postby misterman10 on Mon Oct 01, 2007 7:09 pm

GreecePwns wrote:
misterman10 wrote:it was also titled the homework thread :wink:
whatev though, I guess my thread wasn't good enough :cry:

can anybody help me with my term paper and write it for me? thanks in advance :lol:
depends on the topic and if I have interest in it. :wink:
I was kidding though :lol:
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Postby GreecePwns on Mon Oct 01, 2007 7:10 pm

misterman10 wrote:
GreecePwns wrote:
misterman10 wrote:it was also titled the homework thread :wink:
whatev though, I guess my thread wasn't good enough :cry:

can anybody help me with my term paper and write it for me? thanks in advance :lol:
depends on the topic and if I have interest in it. :wink:
I was kidding though :lol:
I was too.
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Postby fireedud on Tue Oct 02, 2007 6:02 pm

I need help finding information about imaginary numbers (sources other than wiki would be appreciated).
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Postby hecter on Tue Oct 02, 2007 6:05 pm

fireedud wrote:I need help finding information about imaginary numbers (sources other than wiki would be appreciated).

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