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Someone help me with this math problem...

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Someone help me with this math problem...

Postby GreecePwns on Thu Sep 20, 2007 4:50 pm

I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.
Last edited by GreecePwns on Thu Sep 20, 2007 4:58 pm, edited 4 times in total.
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Postby Norse on Thu Sep 20, 2007 4:52 pm

Bracket it more clearly...
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Postby Dancing Mustard on Thu Sep 20, 2007 4:53 pm

7.5

Easy, now give me a biscuit for being a genius.
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Postby wicked on Thu Sep 20, 2007 4:55 pm

is 2K = 2000 or is K another variable?
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Postby GreecePwns on Thu Sep 20, 2007 4:55 pm

wicked wrote:is 2K = 2000 or is K another variable?
another variable
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Re: Someone help me with this math problem...

Postby Norse on Thu Sep 20, 2007 4:55 pm

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^2k+2) - (27x^2k)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.


dude, bracket the powers more clearly...is it 9x to the power of 2k+2..or 9x to the power of 2 multiplied by k+2?
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Postby 0ojakeo0 on Thu Sep 20, 2007 4:56 pm

what grade are you in?
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Postby wicked on Thu Sep 20, 2007 4:56 pm

Well all I could do with it is ...

x^2k = 1/9

assuming it's really (9x^2k)+2 - 27x^2k ???


But I don't really remember what "factor completely" means. :lol:
Last edited by wicked on Thu Sep 20, 2007 4:58 pm, edited 1 time in total.
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Postby GreecePwns on Thu Sep 20, 2007 4:57 pm

0ojakeo0 wrote:what grade are you in?
In American terms, 10th.
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Postby Norse on Thu Sep 20, 2007 4:58 pm

wicked wrote:Well all I could do with it is ...

x^2k = 1/9


But I don't really remember what "factor completely" means. :lol:


factorise
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Postby 0ojakeo0 on Thu Sep 20, 2007 4:58 pm

GreecePwns wrote:
0ojakeo0 wrote:what grade are you in?
In American terms, 10th.


Ok dont got to worry for two more years. :)
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Postby Norse on Thu Sep 20, 2007 4:59 pm

you done logrythyms yet?
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Postby GreecePwns on Thu Sep 20, 2007 4:59 pm

0ojakeo0 wrote:
GreecePwns wrote:
0ojakeo0 wrote:what grade are you in?
In American terms, 10th.
Ok dont got to worry for two more years. :)
But it's Honors level work so, i guess you can say 11th or 10 1/2th
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Postby GreecePwns on Thu Sep 20, 2007 4:59 pm

Norse wrote:you done logrythyms yet?
nope.
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Postby Norse on Thu Sep 20, 2007 5:00 pm

hehe, well I hope you're a fast learner... :lol:
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Postby GreecePwns on Thu Sep 20, 2007 5:01 pm

Norse wrote:hehe, well I hope you're a fast learner... :lol:
somewhat...but the point is i could've done it if the +2 in the first term's exponent using GCF.
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Postby 0ojakeo0 on Thu Sep 20, 2007 5:02 pm

GreecePwns wrote:
0ojakeo0 wrote:
GreecePwns wrote:
0ojakeo0 wrote:what grade are you in?
In American terms, 10th.
Ok dont got to worry for two more years. :)
But it's Honors level work so, i guess you can say 11th or 10 1/2th


Ill probaly be in honors though...
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Re: Someone help me with this math problem...

Postby nagerous on Thu Sep 20, 2007 5:02 pm

have you rationalised the denominator?
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Postby Dancing Mustard on Thu Sep 20, 2007 5:04 pm

Have you calibrated the optimal value for the first variable? That ought to be your first step.
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Re: Someone help me with this math problem...

Postby GreecePwns on Thu Sep 20, 2007 5:04 pm

nagerous wrote:have you rationalised the denominator?
:-s There's no denominator?

Have you calibrated the optimal value for the first variable? That ought to be your first step.


:-s
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Re: Someone help me with this math problem...

Postby bob3603 on Thu Sep 20, 2007 5:12 pm

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.


9x^(2y)*(x-sqrt(3))(x+sqrt(3))
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Postby Norse on Thu Sep 20, 2007 5:14 pm

9X Log (2y + 2) = 27X Log (2y)

1/3 log(2y + 2) = Log (2y)

...
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Re: Someone help me with this math problem...

Postby Titanic on Thu Sep 20, 2007 5:18 pm

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.


Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]

Additional: You can write (9x^2y)(x^2-3x) if you want, but thats unnecessary because the first bracket is all 1 product.
Last edited by Titanic on Thu Sep 20, 2007 5:21 pm, edited 1 time in total.
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Re: Someone help me with this math problem...

Postby GreecePwns on Thu Sep 20, 2007 5:20 pm

Titanic wrote:
GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.


Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]
You're subtracting them, not multiplying.
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Re: Someone help me with this math problem...

Postby Titanic on Thu Sep 20, 2007 5:23 pm

GreecePwns wrote:
Titanic wrote:
GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.


Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]
You're subtracting them, not multiplying.


No I'm not. When expanding the bracket, you do not subtract first. You times the first product by the outside product, and then you times the second product (with the negative sign) by the outside product.

Its impossible to simplify a subtraction which involves polynomials of different powers.
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