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is 20 v 1 and not take it,random dice?

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is 20 v 1 and not take it,random dice?

Postby Tarrus on Tue Mar 04, 2008 10:03 am

Is 20 v 1 & not take it random dice?
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Re: is 20 v 1 and not take it,random dice?

Postby kingprawn on Tue Mar 04, 2008 10:07 am

Tarrus wrote:Is 20 v 1 & not take it random dice?


Lord......I thought 21 against 5 and not taking it was bad. Mind you i've just had 14 against 12 and advanced 11 in so it does swing in roundabouts. Chin up old son.
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Postby lord voldemort on Tue Mar 04, 2008 11:59 am

i see your mouth moving but all i hear is whinge whinge whinge
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?

Postby Tarrus on Tue Mar 04, 2008 12:53 pm

i wasnt whinging,i was asking a question. Thankyou for your most helpful imput though.
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Postby lozzini on Tue Mar 04, 2008 12:55 pm

if you calculate the probablity of that happeningh then think how many dice rolls there have been in over 1.5 million games these things will happen
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Postby BENJIKAT IS DEAD on Tue Mar 04, 2008 12:59 pm

12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.

So this is once every 66 thousand times this attack is attempted.

I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.

The important thing to remember is that "random" does not equal "average".
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Postby KoE_Sirius on Tue Mar 04, 2008 1:02 pm

ANother dice thread?....How many so we have now?
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Postby lozzini on Tue Mar 04, 2008 1:02 pm

way too many :roll:
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Postby BENJIKAT IS DEAD on Tue Mar 04, 2008 1:10 pm

BENJIKAT IS DEAD wrote:12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.

So this is once every 66 thousand times this attack is attempted.

I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.

The important thing to remember is that "random" does not equal "average".



oops I read 12 instead of 20 :oops:


That's a much much smaller number...
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Postby DiM on Tue Mar 04, 2008 1:12 pm

BENJIKAT IS DEAD wrote:
BENJIKAT IS DEAD wrote:12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.

So this is once every 66 thousand times this attack is attempted.

I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.

The important thing to remember is that "random" does not equal "average".



oops I read 12 instead of 20 :oops:


That's a much much smaller number...


but still possible. even if much smaller.
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Postby the doorman on Tue Mar 04, 2008 1:26 pm

20 v 1 though!!!

lol,funny now,but at the time i could have cried i can tell ya ll
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Postby snoopdobb on Sun Mar 16, 2008 8:48 pm

It can be brutal. I think there should be some sort of 'overwhelming strength' bonus or something. I mean, how many times outside of Hollywood does one guy take down 20?

Maybe if you have > 5 times the armies of the defending territory, you get to roll 4 dice, or get +1 to your highest roll, or something. Many of the real-world risk variants include such bonuses, usually if you have a 'commander' in the attacking territory, or something. An OVERWHELMING difference in the size of one side could grant the same advantage. It can be extremely frustrating to outplay your opponent, only to lose to dice results so far outside the standard deviation as to be mind-boggling.

My €.02

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