Conquer Club

I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

Bracket it more clearly...

7.5

Easy, now give me a biscuit for being a genius.

is 2K = 2000 or is K another variable?

wicked wrote:is 2K = 2000 or is K another variable?

another variable

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^2k+2) - (27x^2k)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

dude, bracket the powers more clearly...is it 9x to the power of 2k+2..or 9x to the power of 2 multiplied by k+2?

what grade are you in?

Well all I could do with it is ...

x^2k = 1/9

assuming it's really (9x^2k)+2 - 27x^2k ???


But I don't really remember what "factor completely" means.

0ojakeo0 wrote:what grade are you in?

In American terms, 10th.

wicked wrote:Well all I could do with it is ...

x^2k = 1/9


But I don't really remember what "factor completely" means.

factorise

GreecePwns wrote:

0ojakeo0 wrote:what grade are you in?

In American terms, 10th.

Ok dont got to worry for two more years.

you done logrythyms yet?

0ojakeo0 wrote:

GreecePwns wrote:

0ojakeo0 wrote:what grade are you in?

In American terms, 10th.

Ok dont got to worry for two more years.

But it's Honors level work so, i guess you can say 11th or 10 1/2th

Norse wrote:you done logrythyms yet?

nope.

hehe, well I hope you're a fast learner...

Norse wrote:hehe, well I hope you're a fast learner...

somewhat...but the point is i could've done it if the +2 in the first term's exponent using GCF.

GreecePwns wrote:

0ojakeo0 wrote:

GreecePwns wrote:

0ojakeo0 wrote:what grade are you in?

In American terms, 10th.

Ok dont got to worry for two more years.

But it's Honors level work so, i guess you can say 11th or 10 1/2th

Ill probaly be in honors though...

have you rationalised the denominator?

Have you calibrated the optimal value for the first variable? That ought to be your first step.

nagerous wrote:have you rationalised the denominator?

There's no denominator?

Have you calibrated the optimal value for the first variable? That ought to be your first step.

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

9x^(2y)*(x-sqrt(3))(x+sqrt(3))

9X Log (2y + 2) = 27X Log (2y)

1/3 log(2y + 2) = Log (2y)

...

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]

Additional: You can write (9x^2y)(x^2-3x) if you want, but thats unnecessary because the first bracket is all 1 product.

Titanic wrote:

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]

You're subtracting them, not multiplying.

GreecePwns wrote:

Titanic wrote:

GreecePwns wrote:I need to know this by tommorrow (my teacher was absolutely no help at all, which means no one in my class knows). Here's an example:

Factor completely

(9x^[2y+2]) - (27x^2y)

Winner gets...i don't know...a cookie or something. Maybe a 1v1 when I get a free space.

Damn thats easy.

9x^2y(x^2-3x)

Remember, when you times polynomials you times the base, and add teh powers.

9x^2y times x^2 = 9x^(2y+2)

9x^2y times -3x = -(27x^2y) [Remember, -3x is actually -3x^1]

You're subtracting them, not multiplying.

No I'm not. When expanding the bracket, you do not subtract first. You times the first product by the outside product, and then you times the second product (with the negative sign) by the outside product.

Its impossible to simplify a subtraction which involves polynomials of different powers.