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MATH QUESTION

Posted:
Thu Aug 30, 2007 3:18 pm
by cawck mongler
So whoever gets this right is the new king of the forums or something.
t^3+t^2-3t-9
---------------
t+3
Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.
The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.
Re: MATH QUESTION

Posted:
Thu Aug 30, 2007 3:31 pm
by diddle
cawck mongler wrote:So whoever gets this right is the new king of the forums or something.
t^3+t^2-3t-9
---------------
t+3
Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.
The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.
=7

Posted:
Thu Aug 30, 2007 3:32 pm
by Arbustos
Disregard ^
The answer is t^2+2t-3
So am I the king of the forums or something?

Posted:
Thu Aug 30, 2007 3:34 pm
by Norse
t = -1, -1.44 or 1.44

Posted:
Thu Aug 30, 2007 3:35 pm
by Norse
The above results are when the subsequent graph line pass through the t-axis...(well, not quite the t-axis, but at y=6)


Posted:
Thu Aug 30, 2007 3:36 pm
by Arbustos
Why are you people giving values? The answer is a factor.

Posted:
Thu Aug 30, 2007 3:37 pm
by Arbustos
Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

You solved for t... you didn't give the answer


Posted:
Thu Aug 30, 2007 3:38 pm
by Arbustos
BTW I hate math. This is just coming back from 9th grade


Posted:
Thu Aug 30, 2007 3:39 pm
by Norse
Arbustos wrote:Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

You solved for t... you didn't give the answer

yes I did, did you want me to give a basic factorized equation? or prefer me to give the actual value?

Posted:
Thu Aug 30, 2007 3:41 pm
by Aegnor
t=3
, it can't be -3 because you get division by zero then.

Posted:
Thu Aug 30, 2007 3:42 pm
by Arbustos
Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

Posted:
Thu Aug 30, 2007 3:42 pm
by Norse
t^3+t^2-3t-9=0
(t^2-3)(t+1)-6=0
(t-3^0.5)(t-3^0.5)(t+1)-6=0
solved

Posted:
Thu Aug 30, 2007 3:42 pm
by Arbustos
Screw this, I hate math


Posted:
Thu Aug 30, 2007 3:43 pm
by Norse
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?
It isnt a parabola, it becomes muted 3 times, like all cubed equations

Posted:
Thu Aug 30, 2007 3:44 pm
by Arbustos
Norse wrote:Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?
It isnt a parabola, it passes the t-axis 3 times, like all cubed equations
No, I mean the factor. Explain this to me, I've forgotten so much
Did you divide by the t+3?

Posted:
Thu Aug 30, 2007 3:45 pm
by Aegnor
(t+3)(t+3)(t-3)
----------------- = 0
t+3
Do your own math from here buddies
I simplified the original equation. Now you can eliminate the denominator, and you get:
(t+3)(t-3)=0
Magical isn't it?

Posted:
Thu Aug 30, 2007 3:46 pm
by Norse
Arbustos wrote:Norse wrote:Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?
It isnt a parabola, it passes the t-axis 3 times, like all cubed equations
No, I mean the factor. Explain this to me, I've forgotten so much
Did you divide by the t+3?
no no, just factorized the original equation.

Posted:
Thu Aug 30, 2007 3:47 pm
by Arbustos
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3
Do your own math from here buddies

@$#% That was too easy... I don't have a mind for math


Posted:
Thu Aug 30, 2007 3:48 pm
by Norse
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3
Do your own math from here buddies

wrong im afraid...
expand them factors, and yyou will end up with..
t^3+6t^2+18t-27
a little off there

Posted:
Thu Aug 30, 2007 3:49 pm
by Norse
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3
Do your own math from here buddies

I simplified the original equation. Now you can eliminate the denominator, and you get:
(t+3)(t-3)=0
Magical isn't it?
hehe, way off the mark there, nothings ever that easy....go back and re-read

Posted:
Thu Aug 30, 2007 3:49 pm
by Arbustos
Norse wrote:Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3
Do your own math from here buddies

wrong im afraid...
expand them factors, and yyou will end up with..
t^3+6t^2+18t-27
a little off there
Well, I blindly accepted it because the steps were correct. Damn this


Posted:
Thu Aug 30, 2007 3:51 pm
by Norse
(t+3)(t+3) = t^2+9t+9
{t^2+9t+9}(t-3) =t^3+6t^2+18t-27

Posted:
Thu Aug 30, 2007 3:52 pm
by Aegnor
Ah crap, I guess you're right! I feel into that trap blindly


Posted:
Thu Aug 30, 2007 3:54 pm
by Arbustos
From the factors, wouldn't the solution be 1, since -3 causes a division by zero scenario?
Factors: (t+3)(t+3)(t-1)

Posted:
Thu Aug 30, 2007 3:56 pm
by Norse
Norse wrote:t^3+t^2-3t-9=0
(t^2-3)(t+1)-6=0
(t-3^0.5)(t-3^0.5)(t+1)-6=0
solved
QFT!
^0.5 means squared root, btw.