Conquer Club

I have one poplar (populus) or how you say in english. to cut down, and i want to know how much its will have cubic meter of wood will have . I look on some online calculators but its difficulty to understand how this work. Even hypothetically measurement of tree not understand.
For example if tree one side (close to land) have diameter of 100 cm, and other side (end of tree) have 20 cm, and tree are long 12 meter, how much cubic meter of wood could be ?

Any Lumberjack expert here?

Qwert wrote:I have one poplar (populus) or how you say in english. to cut down, and i want to know how much its will have cubic meter of wood will have . I look on some online calculators but its difficulty to understand how this work. Even hypothetically measurement of tree not understand.
For example if tree one side (close to land) have diameter of 100 cm, and other side (end of tree) have 20 cm, and tree are long 12 meter, how much cubic meter of wood could be ?

Any Lumberjack expert here?

You need to get laid

3.9 cubic metre

Qwert wrote:I have one poplar (populus) or how you say in english. to cut down, and i want to know how much its will have cubic meter of wood will have . I look on some online calculators but its difficulty to understand how this work. Even hypothetically measurement of tree not understand.
For example if tree one side (close to land) have diameter of 100 cm, and other side (end of tree) have 20 cm, and tree are long 12 meter, how much cubic meter of wood could be ?

Any Lumberjack expert here?

You don't need a lumberjack. Anyone who passed Grade 7 math class should do.

Volume of a cylinder is (π)(radius of cylinder)(length of cylinder)

Since you have a tapered cylinder, you have to know if it is tapered smoothly. If it's tapered parabolically or some shit, you would need calculus, but I doubt if you need that level of precision. Assuming that it tapers smoothly, you simply take the average of the two ends.
(50+10)/2=30.
π*0.30m*12m=11.3 m^2

Those who forget their high school math are destined to repeat it...

I guess you're going to be repeating high school math then, Duk.

Need to square the radius in that equation. Maxleod's answer was closer.

""(50+10)/2=30.
π*0.30m*12m=11.3 m^2"""

what are what on this formula,,, and final score end on m2,,,i think that need to be m3.
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maxleod can you tell me how you calculated 3.9 cubic metres?
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bernie sanders need to get laid? first i need to get down................................. a tree.

4 cubic meter, a little more when you add the branches.

if you need more, you can ask sekretar, he always has extra wood for the winter.

Dukasaur wrote:

Qwert wrote:I have one poplar (populus) or how you say in english. to cut down, and i want to know how much its will have cubic meter of wood will have . I look on some online calculators but its difficulty to understand how this work. Even hypothetically measurement of tree not understand.
For example if tree one side (close to land) have diameter of 100 cm, and other side (end of tree) have 20 cm, and tree are long 12 meter, how much cubic meter of wood could be ?

Any Lumberjack expert here?

You don't need a lumberjack. Anyone who passed Grade 7 math class should do.

Volume of a cylinder is (π)(radius of cylinder)(length of cylinder)

Since you have a tapered cylinder, you have to know if it is tapered smoothly. If it's tapered parabolically or some shit, you would need calculus, but I doubt if you need that level of precision. Assuming that it tapers smoothly, you simply take the average of the two ends.
(50+10)/2=30.
π*0.30m*12m=11.3 m^2

Those who forget their high school math are destined to repeat it...

Bentelbow wrote:I guess you're going to be repeating high school math then, Duk.

Need to square the radius in that equation. Maxleod's answer was closer.

Okay, better effort:
π*0.30^2 = 0.28 m^2 <-- cross-sectional area at the base
π*0.10^2 = 0.03 m^2 <-- cross-sectional area at the top
(0.28+0.03) = 0.31 m^2 <-- average of the cross-sectional areas
0.31m^2 * 12m = 3.72 m^3 <-- average of the cross-sectional areas times the length of the cylinder.

Qwert wrote:what are what on this formula,,, and final score end on m2,,,i think that need to be m3.

Okay, labelled each step better.

Keep in mind that it's an estimation, based on a simple average of the beginning and end of the cylinder. Writing it as a formula and using integral calculus would give you a more accurate answer, but it's been damn near 40 years since high school and I'll be damned if I can remember how to do integrals...

Besides, a rough approximation should be plenty good enough, especially since I suspect you're estimating the size of the tree anyway. Really, the answer should only have one significant digit, so I would say that I'm sure it's more than 3, probably closer to 4, maybe even close to 5 if you underestimated the size of the tree.

you know there's a much easier way to calculate this for the approximation that is needed, if you don't remember more advanced formulas. treat it like a cone, all you have to do is calculate the volume of a cylinder and divide by 3. so if it takes it 12 mts to make it to 4/5 of the apex, it's a 15 mts cone.

(1/2*1/2 * 3.14 * 15) / 3 = 3.9 m3

there you have a valid approximation, done in 1 minute in your head, if you want to make it closer, substract the volume of the imaginary 20cm * 3 m cone, but the volume of this is negligible.

Fuking idiots, you normally try to figure out how many planks, 2x4, 2x6, 2x10, 4x4 and such. So, you can get more value out of that tree you killed!

What? You want to figure out how many 40lbs bags of mulch or saw dust you can make?

I asked my local woodsman, Charles (as he is an expert on such volumes) about this recently. I simply enquired as to the maximum possible resulting wood that could be produced, if someone of his profession was able, and inclined to chuck wood, as his profession indicates.

He seemed baffled by my question- offended even. I'm not sure I phrased the question in the right way.

Depends what kind of woodsman he is.. if he is of the fleshy variety, perhaps volumes are not his expertise.

Bentelbow wrote:Depends what kind of woodsman he is.. if he is of the fleshy variety, perhaps volumes are not his expertise.

He's difficult to read. Sometimes it seems like he's afraid of his own shadow.

Qwert wrote:I have one poplar (populus) or how you say in english. to cut down, and i want to know how much its will have cubic meter of wood will have . I look on some online calculators but its difficulty to understand how this work. Even hypothetically measurement of tree not understand.
For example if tree one side (close to land) have diameter of 100 cm, and other side (end of tree) have 20 cm, and tree are long 12 meter, how much cubic meter of wood could be ?

Any Lumberjack expert here?

ask this guy : logscaler

i'm serious, probly what he does for a living...
llama = helping

ooc, what are you going to do with poplar? it's one of the crappiest types of wood there is.

riskllama wrote:ooc, what are you going to do with poplar? it's one of the crappiest types of wood there is.

I'm serious too, I was under the impression that it should be chucked, preferably by a chucker of wood.

Symmetry wrote:

riskllama wrote:ooc, what are you going to do with poplar? it's one of the crappiest types of wood there is.

I'm serious too, I was under the impression that it should be chucked, preferably by a chucker of wood.

It was a good joke. I chuckled.

bernie i need to put this tree down because its not healty..
risklama i plant this tree for ornament purposes, and now will be food for fire in winter.
i have big yard some 3500 m2 and i dont have only popplar,i have a lot of diferent trees planted.

just to name few
1 ginko
20 to 30 black locust
4 poplar
2 silver birch
1 weeping willow
1 horse chesnuts
3-4 field elm
2 tilia
4 pine (dont know what species)
and some more to .......

(also have many diferent fruit plants to)

Sometimes tree need to be cut bernie.



what represent 1/2 , and what are 15?
(1/2*1/2 * 3.14 * 15) / 3 = 3.9 m3

Are you calculating so you will know what size jackwagon to hire?

Qwert wrote:bernie i need to put this tree down because its not healty..
risklama i plant this tree for ornament purposes, and now will be food for fire in winter.
i have big yard some 3500 m2 and i dont have only popplar,i have a lot of diferent trees planted.

just to name few
1 ginko
20 to 30 black locust
4 poplar
2 silver birch
1 weeping willow
1 horse chesnuts
3-4 field elm
2 tilia
4 pine (dont know what species)
and some more to .......

(also have many diferent fruit plants to)

Sometimes tree need to be cut bernie.



what represent 1/2 , and what are 15?
(1/2*1/2 * 3.14 * 15) / 3 = 3.9 m3

1m diameter so 1/2m (0.5m) radius
15mt is what a cone height would be given that it takes 12mt from 1mt to 20cm (considering a perfect uniform taper).. so if it takes 12m to do 80% of the way up, it takes 15mt to do 100%.

the formula of the cone volume is area of the base * height, divided by 3

area of the base is pi * radius^2

Symmetry wrote:I asked my local woodsman, Charles (as he is an expert on such volumes) about this recently. I simply enquired as to the maximum possible resulting wood that could be produced, if someone of his profession was able, and inclined to chuck wood, as his profession indicates.

He seemed baffled by my question- offended even. I'm not sure I phrased the question in the right way.

Hope your fifteenth degree is going well.

nietzsche wrote:

Qwert wrote:bernie i need to put this tree down because its not healty..
risklama i plant this tree for ornament purposes, and now will be food for fire in winter.
i have big yard some 3500 m2 and i dont have only popplar,i have a lot of diferent trees planted.

just to name few
1 ginko
20 to 30 black locust
4 poplar
2 silver birch
1 weeping willow
1 horse chesnuts
3-4 field elm
2 tilia
4 pine (dont know what species)
and some more to .......

(also have many diferent fruit plants to)

Sometimes tree need to be cut bernie.



what represent 1/2 , and what are 15?
(1/2*1/2 * 3.14 * 15) / 3 = 3.9 m3

1m diameter so 1/2m (0.5m) radius
15mt is what a cone height would be given that it takes 12mt from 1mt to 20cm (considering a perfect uniform taper).. so if it takes 12m to do 80% of the way up, it takes 15mt to do 100%.

the formula of the cone volume is area of the base * height, divided by 3

area of the base is pi * radius^2

oh,i think that understand, so before calculation, need to diameter from bout side put together and then to divide by 2.
So my example from first post will look like this:
0.6x0.6x3.14x12/3=4.5 m3
right?

Qwert wrote:

nietzsche wrote:

Qwert wrote:bernie i need to put this tree down because its not healty..
risklama i plant this tree for ornament purposes, and now will be food for fire in winter.
i have big yard some 3500 m2 and i dont have only popplar,i have a lot of diferent trees planted.

just to name few
1 ginko
20 to 30 black locust
4 poplar
2 silver birch
1 weeping willow
1 horse chesnuts
3-4 field elm
2 tilia
4 pine (dont know what species)
and some more to .......

(also have many diferent fruit plants to)

Sometimes tree need to be cut bernie.



what represent 1/2 , and what are 15?
(1/2*1/2 * 3.14 * 15) / 3 = 3.9 m3

1m diameter so 1/2m (0.5m) radius
15mt is what a cone height would be given that it takes 12mt from 1mt to 20cm (considering a perfect uniform taper).. so if it takes 12m to do 80% of the way up, it takes 15mt to do 100%.

the formula of the cone volume is area of the base * height, divided by 3

area of the base is pi * radius^2

oh,i think that understand, so before calculation, need to diameter from bout side put together and then to divide by 2.
So my example from first post will look like this:
0.6x0.6x3.14x12/3=4.5 m3
right?

no, the numbers i posted were not an example, they were for your case.


diameter of the base: 1m
diameter at the top 0.2m
height 12m

to use the formula of the cone (because it's an easy formula that i happen to remember) I had to add an imaginary last part at the top, the vertex. that part would be a small cone itself, from 0.2mt to 0m (the vertex). I say imaginary because it's not included in the data you provide, but I guess the top of the tree does have a vertex.

So i need to know how tall would be the cone now, we know that from 1m to 0.2m it takes 12 mt, and since we're imagining a uniform taper, it should be proportional. From 1m to 0.2m is 80%, so

12m --- 80
? --------100

x=12x100/80 = 15m

so with the height of the cone use the formula for the volume of the cone

(area * height) / 3

(π * radius² (of the base) * 15) / 3

(3.14 * 0.5² * 15) / 3

= 3.925m³


now if you remember, we added an imaginary cone of 0.2m of base and 3m of height, the volume of this cone is negligible, and given that all this is only an approximation, it shouldn't matter, but if you want you can calculate its volume to substract it you can.

diameter of the base 0.2m (0.1 radius)
height 3m

(3.14 * 0.1² * 3 ) / 3 = 0.0314m³ or 31,400cm³


so 3.925m³ of the cone with the imaginary part we added so we can use the cone formula.. minus the 0.0314m³ of that imaginary part's volume at the top, is 3.89m³.



sorry if this is more confusing than using Dukasaur's formula. to my head it's easier to think this way.


edit: corrected red

holy f*ck, just use Doyle's log scale....