Conquer Club

I don't quite understand the Radiation Nexus thingie...

it's right in the legend..

if u own one u get one less army then u should have
if u own two u get one less army then u should have
if u own three then u break even

like u usually get three armies starting a game out..but if u own one of those u would only get two on your first turn

If you hold 1 or 2 territories marked with the radiation symbol, then you get a penalty of -1. If you hold 3 such territories, you get neither a bonus nor a penalty (although the passive +1 from holding 3 territories still applies unless you're under 12 territories). If you hold 4 radiated territories or more, you get bigger and bigger bonuses. If you hold all 6, you get a whopping +9 bonus. This isn't easy to get, though, because you'd have a foot in literally every continental bonus, so the other players aren't going to be very happy about it.

I think the function for calculating it is

n
Σ ((xi)-1) - n
i=1

With n being the number of nexus you hold.



that (xi) part is really x with an index, does anyone know how to write that properly?

x[i] is the usual way (if you don't have the closing bbcode tag it won't become italicised). But I don't get what x[i] is supposed to be.

You get -1 for each individual, and +1 for each pair. So it's (n choose 2) - n, or n!/2(n-2)! - n.

It's a normal sigma function, I just don't know how to get the i so it's "lower down", like when you have functions to the power of two or more and end up having multiple possible values for x and enumerate them with an index.

i refer anyone interested in defending their explanation to Game 917541.

My opponent holds all six radiation symbols, yet does not get nine bonus armies.

2007-10-02 04:28:42 - King Conqueror receives -5 armies for holding irradiated territory
2007-10-02 04:28:42 - King Conqueror receives 10 armies for holding a radiation nexus

What gives? How does this relate to the on-map legend?

Sorry that was a bit snotty looking.

Thanks to all who responded, but I still don't get it.

Your opponent only held 5 of the radiation territories, not all 6 (STTL was neutral - upper left corner). So the overall effect is +5, as the chart shows. Don't get confused with the "nexus" wording, just look at the overall effect, which is 10-5=5 in this case.

Do you understand now?

MeDeFe wrote:It's a normal sigma function, I just don't know how to get the i so it's "lower down", like when you have functions to the power of two or more and end up having multiple possible values for x and enumerate them with an index.

Your (xi) should just be an i, because that's what increments. The x has no value; I think that's what philh's point was.

No need to sum anyways, there's a nicer closed form, just simplifying what philh had. (n choose 2) - n = n(n-1)/2 - n = n(n-3)/2

Thanks Wicked, that was where i was going wrong, STTL was neutral