Conquer Club

If you take somebody out, and you get a total of seven (7) cards, will you always get two potential sets (ie if you play them right, you'll be able to cash in twice)?

It's been my experience that this is true, but as there are people on the forums much smarter than me, I was wondering if they could tell me otherwise.

5 reds and 2 greens only = 1 cashin.

Ah. Perfect. Thank you IC.

8 is the threshold number guaranteeing you will be able to cash in two sets, just as 5 is the threshold number guaranteeing you will be able to cash in one set.

Your odds of having two sets to cash in with 7 cards is the same as your odds of having a single set to cash in with 4 cards; namely 77%.

I disagree. I think it is higher than 77%.

If you have 2 blue and 2 green cards, you cannot cash in any sets. But if you have 2 blue, 2 green, and 3 red cards, you can cash in 2 sets, if you cash in correctly (as in 2 mixed sets instead of a red set).

A 5-2-0 distribution of cards is the only distribution that disallows you to cash twice. So if you are getting 7 cards, you should be able to bank on being able to cash twice.

and you can screw it up by turning in wrong set so you get 1 instead of 2 turn ins

3 red
3 blue
1 green

turn in 1 each =1 set

or turn in 3 red and 3 blue + 2 sets

much better chance of having 2 sets with 7 than 1 set with 4.

possible combinations of 4 cards that make a set: 4 0 0, 3 1 0, 2 1 1
possible combinations of 4 cards that don't make a set: 2 2 0

so thats 3 out of 4 combinations make 1 set out of 4 cards.

possible combinations of 7 cards that makes 2 sets: 7 0 0, 6 1 0, 4 3 0, 5 1 1, 4 2 1, 3 3 1, 3 2 2.
possible combinations of 7 cards that don't make 2 sets: 5 2 0

and thats 7 out of 8 combinations make 2 sets out of 7 cards

of course some combinations are more likely than others, but this gives you a rough idea of just how more likely it is to have 2 sets with 7 than 1 set with 4.

maniacmath17 wrote:much better chance of having 2 sets with 7 than 1 set with 4.

possible combinations of 4 cards that make a set: 4 0 0, 3 1 0, 2 1 1
possible combinations of 4 cards that don't make a set: 2 2 0

so thats 3 out of 4 combinations make 1 set out of 4 cards.

possible combinations of 7 cards that makes 2 sets: 7 0 0, 6 1 0, 4 3 0, 5 1 1, 4 2 1, 3 3 1, 3 2 2.
possible combinations of 7 cards that don't make 2 sets: 5 2 0

and thats 7 out of 8 combinations make 2 sets out of 7 cards

of course some combinations are more likely than others, but this gives you a rough idea of just how more likely it is to have 2 sets with 7 than 1 set with 4.

anybody else that didnt understand anything this guy said??

Edit: i just understood that the numbers stands for colors example 7 0 0 , 7 red cards 0 blue 0 green...ok got ur back on this 1 lol