Conquer Club

There is also the option of attacking with 4 once and 9 once. Which in hindsight is the option maybe i should have went with. Stack was 6 which would probably turn into 9 for the second attack.

only if you don't lose both dice in the first 2 rolls

Phatscotty wrote:only if you don't lose both dice in the first 2 rolls

Hey scotty, remember that 500+ round game we has in world.2?

i am one of double-stacking's biggest fans, so i appreciate this chance to remind me of how to analyze why it is important

the basic concept is that a stack of 3 is a non-attacker. if you attack the stack down to 2, you get an extra attacker; each attacking stack gets an extra chance at this extra troop

a basic rule to remember:

show

THE MEAT OF THE ARGUMENT:

RECAP:
3v2
37.17 ;aw2
29.26; dw2
33.58 a1d1


actually those numbers only matter if you take the p dw2 v q a1d1 or p=(.4656) q=[.5344] {Phatscotty is wrong in his analysis, as if i win the first 2, it tells me nothing about whether or not i will get the "2" bonus}
to put this into effect: 6,6 gets the extra attacker chance if both attacks are fails, but also if the first two are splits and the third is a fail;
it does not get the extra attack if the first is a fail, and the second a split [or vice versa], or the first 3 are splits
p[ex]=.2168 + .1330 = .3498
p[-ex]=.4976 + .1526 = .6502

so, 35% you get an extra troop, 65% you don't. note that because you gave up an attacker to get to this method, you only have a 35% chance of getting that attacker back

4,9
quite simple has a 47% chance at extra troop

5, 8
only has a 28% chance of the extra attacker

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Right now, these are 2 complete theories of different aspects. to complete this project i would integrate the two options together. the chance that you get to 2 is also based on the number of defenders, and is the main reason for the law of alternating returns. that sounds like a thesis to me.

i've been thinking: how the f*ck do you go from 6 twice to 10 once? where does the extra troop go?

trevor33 wrote:

Phatscotty wrote:only if you don't lose both dice in the first 2 rolls

Hey scotty, remember that 500+ round game we has in world.2?

oh yeah. Check this one out too. We were chatting about Hillary Clinton winning in 2008 lulz

http://www.conquerclub.com/game.php?game=5213210

Phatscotty wrote:

trevor33 wrote:

Phatscotty wrote:only if you don't lose both dice in the first 2 rolls

Hey scotty, remember that 500+ round game we has in world.2?

oh yeah. Check this one out too. We were chatting about Hillary Clinton winning in 2008 lulz

http://www.conquerclub.com/game.php?game=5213210

Jesus, don't think i've played a singles game on that map since...