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2 sets?

PostPosted: Tue Feb 08, 2011 6:52 am
by CptJMoney
Does anyone know if you can cash in 2 sets of spoils at once? I've never tried before and I haven't seen anyone else do it.

Re: 2 sets?

PostPosted: Tue Feb 08, 2011 6:58 am
by Joodoo
It is possible to cash in more than one set of spoils consecutively if you have at least 6 spoils (from mid-turn cashing, after eliminating an opponent with spoils) and they belong to 2 or 3 sets, see round 9 of this game as an example.

Re: 2 sets?

PostPosted: Tue Feb 08, 2011 7:12 am
by SirSebstar
CptJMoney wrote:Does anyone know if you can cash in 2 sets of spoils at once? I've never tried before and I haven't seen anyone else do it.

Loodoo is correct.
How does it work: You select your 3 spoils aka a set, you wish to use. Click the botton and it is done. If you have enough spoils left to make a second set, you can then immediately select the next 3 spoils.

In theory it is possible to cash in 11 sets in 1 turn. 7x5/3=11.66. However that would require 8 players and 7 of those to have 5 sets and you being able to kill every single player in a row in one game. It happens

Re: 2 sets?

PostPosted: Thu Feb 10, 2011 7:35 am
by drunkmunky
SirSebstar wrote:In theory it is possible to cash in 11 sets in 1 turn. 7x5/3=11.66. However that would require 8 players and 7 of those to have 5 sets and you being able to kill every single player in a row in one game. It happens


Not quite correct, maximum would be 6x5/3 or 10. Upon killing the 7th player and getting his spoils, the game would end. But yes, 10 consecutive sets, but sets at once the most possible is 3.

This is due to if you have 5 cards, you'd have played a set at the start of the turn. If you have 4, then kill a player with 5, you will have 9 and the possibility of 3 sets.

So 10 is the maximum consecutive sets you can play in a turn, 3 is the most you can play at a single moment.

Re: 2 sets?

PostPosted: Thu Feb 10, 2011 7:41 am
by SirSebstar
drunkmunky wrote:
SirSebstar wrote:In theory it is possible to cash in 11 sets in 1 turn. 7x5/3=11.66. However that would require 8 players and 7 of those to have 5 sets and you being able to kill every single player in a row in one game. It happens


Not quite correct, maximum would be 6x5/3 or 10. Upon killing the 7th player and getting his spoils, the game would end. But yes, 10 consecutive sets, but sets at once the most possible is 3.

This is due to if you have 5 cards, you'd have played a set at the start of the turn. If you have 4, then kill a player with 5, you will have 9 and the possibility of 3 sets.

So 10 is the maximum consecutive sets you can play in a turn, 3 is the most you can play at a single moment.


with 8 players you can have 5 cards yourself and kill 6 players... so 7x5/3= 11.66
Other then that, you are almost correct.
Nuclear games allow you to kill and the play a set consequativly,(arg, in succession) so again if you can kill 6 players in an 8 player game, you can at most play 11 sets, one after the other....
highly unlikely, but possible.

Re: 2 sets?

PostPosted: Thu Feb 10, 2011 7:42 am
by drunkmunky
damn, that'll teach me for trying to be a smart arse...haha

Re: 2 sets?

PostPosted: Thu Feb 10, 2011 8:16 am
by SirSebstar
np, i think your additions are fine. it prompted me to set it down even more precicely..
there can never be enough helping hands or something, .. whatever. your additions are appreciated