Conquer Club

New statistic: Expected number of wins

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New statistic: Expected number of wins

Postby GenuineEarlGrey on Thu Aug 14, 2008 8:40 pm

Concise description:
  • We have the percentage of wins for each player on their home page.
  • Add their expected number of wins.
Specifics:
  • Percentage of wins: number wins / number completed games.
  • Expected wins: number of wins / Total number of players in complete games.
This will improve the following aspects of the site:
  • Gives a better summary of players.
  • Many people like stats, this would be a more useful one.
Example:
Player 1 has played 100 games and won 30 but these are all 1 v 1 games.
Player 2 has played 200 games and won 40 but these are all multi player games, say 8 players.

Player 1 has won 30% of games but was expected to win 50%
[expected wins is 1/2 + 1/2..... = 100 / 2*100 = 50%]

Player 2 has won 20% of games but was expected to only 12.5%
[expected wins is 1/8 + 1/8 ..... = 200 / 8*200 = 12.5%]

Note
The statistics would only need running totals to caculate it.
Extension
If you want to beef this up you could calculate expected number of points BUT I don't think you could do this reterospectivly.

EG
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Re: New statistic: Expected number of wins

Postby Androidz on Thu Aug 14, 2008 8:49 pm

I think the Map rank covers this. Add On. Check Plugins and Add ons tread.
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New Win Percentage

Postby King Dain II on Sun Aug 17, 2008 10:25 am

Concise description:
  • A slightly complicated win ratio next to the win percentage we have now

Specifics:
  • Here is how it works: (2 x Win%In2PlayerGames + 3 x Win%In3PlayerGames + 4 x Win%In4playerGames...) / 8
  • Run through: The odds of winning a 2 player game is 50%, while an 8 player is 12.5%. Currently these two count the same towards the overall win percentage when really a player that plays mostly 8 player games will have a lower win rate than someone like me who plays 2 player games. In this new way of calculating the win rate, this is evened out by multiplying the number of players by the win % in those types of games.
  • An absolutely average win rate would come out as 1.00 if you win 50% of 2 player, 33% of 3, 25% of 4... A person who has an overal of 2, wins twice as many games as he should according to the statistic: 8 player games with 25% won would be a 2 for that category, since you ae only supposed to win 12.5%, but it will average out with the other win percentages in games with different #s of players
  • Elongated formula: (2 x Win%InAll2PlayerGamesPlayed + 3 x Win%InAll3PlayerGamesPlayed + 4 x Win%InAll4PlayerGamesPlayed...) / 8 = an adjusted win ratio that accurately shows your win rate compared to the probable win rate.

This will improve the following aspects of the site:
  • Win % is more useful seeing as it does not vary depending on your preferred number of players in a game.
  • People who play 8 player are recognized as being able to win more games than average instead of being looked down upon for really low win %s. (I have seen this happen plenty of times in the General Discussion Forum)

The thing I still need to figure out (posted this rather quickly), is that if you have only played one or two x-player games, then that will count as much to the overall as if you played 100.
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Re: New statistic: Expected number of wins

Postby King Dain II on Sun Aug 17, 2008 10:29 am

Been meaning to to post this for a while.

Anyways, I have this worked out except for one little thing. The thread is: viewtopic.php?f=4&t=59745
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Re: New statistic: Expected number of wins

Postby lancehoch on Sun Aug 17, 2008 10:39 am

Merged the two topics since they are discussing the same idea, even though it is two different ways to calculate it.
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